x^2+4x-3=-7

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Solution for x^2+4x-3=-7 equation:



x^2+4x-3=-7
We move all terms to the left:
x^2+4x-3-(-7)=0
We add all the numbers together, and all the variables
x^2+4x+4=0
a = 1; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-4}{2}=-2$

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